2y^2=4y-4

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Solution for 2y^2=4y-4 equation: 



2y^2=4y-4

We move all terms to the left:

2y^2-(4y-4)=0

We get rid of parentheses

2y^2-4y+4=0

a = 2; b = -4; c = +4;
Δ = b2-4ac
Δ = -42-4·2·4
Δ = -16
Delta is less than zero, so there is no solution for the equation

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